The sum of ages of 5 children born at intervals of 3 years each is 50 youngest age
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Let the ages of children be x, (x + 3), (x + 6), (x + 9), (x + 12) years.
According to Question now,
➳ x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
➳ 5x + 30 = 50
➳ 5x = 50 - 30
➳ x = 20/5
➳ x = 4 years
Therefore,the age of youngest child is 4 years.
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