Question

the sum of ages of 5 children born at intervals of 3years each is 50 years. what is the afe of youngest child

Answer 1

let the age of first child be x
therefore
ages of childrens be
x,(x+3),(x+6),(x+9),(x+12)
according to the question
x+x+3+x+6+x+9+x+12=50
5x+30=50
5x=20
x=4
therefore the age of youngest child is 4 years

Answer 2

solutions :-

The five children's ages will be :-
x, x + 3, x + 6, x + 9, x + 12.
Added together this gives:
5x + 30
Total of ages = 50
5x + 30 = 50
5x = 50 - 30
5x = 20
x = 4.

The youngest child is 4 years old.

Thanks