Question

The sum of ages of 5 children born at the intervals of 3 years each is 50 years. what is the age of the youngest child ?

Answer 1

Heats..!!

Let the age of the youngest child be x..

So.. the age of of the consecutive children will be x + 3, x + 3 + 3, x + 3 + 3 + 3, x + 3 + 3 + 3 + 3...

That is.. x + 3, x + 6, x + 9, x + 12..

So.. As per the question..

x + x + 3 + x + 6 + x + 9 + x + 12 = 50

5x + 20 = 50

=> 5x = 50 - 20

=> 5x = 30

=> x = 6

THEREFORE... THE AGE OF THE YOUNGEST CHILD IS 6

Hope it helps...!

And here CutieBarbie :)

Answer 2

solutions :-

The five children's ages will be :-
x, x + 3, x + 6, x + 9, x + 12.
Added together this gives:
5x + 30
Total of ages = 50
5x + 30 = 50
5x = 50 - 30
5x = 20
x = 4.

The youngest child is 4 years old.

Thanks