Question

The sum of ages of 5 children born at the intervals of 3 years each is 50years what is the age of the youngest child

Answer 1

Answer:

Let the ages of children be x, (x + 3), (x + 6), (x + 9), (x + 12) years.

According to Question now,

➳ x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

➳ 5x + 30 = 50

➳ 5x = 50 - 30

➳ x = 20/5

➳ x = 4 years

Therefore,the age of youngest child is 4 years.

Answer 2

Answer:

x = 4

Age of youngest child = 4 years.

Step-by-step explanation:

Given :

>> Ages of 5 children are in interval of 3 years.

>> Sum of ages = 50

To Find:-

>> Age of Youngest Child.

Procedure:-

Let the age of youngest child be x

A second child be = x + 3

Third child be = x + 6

Fourth child be = x + 9

Fifth child = x + 12

Given that sum of ages is 50 years. From the mentioned information, we can infer that:-

$\sf \implies (x) + (x+3) + (x+6) +(x+9) (x+12) = 50$

Combining Like terms :-

$\sf \implies (x+x+x+x)+(3+6+12)=50$

$\sf \implies 4x+30=50$

Subtract 30 from both the sides.

$\sf \implies 5x+30-30=50-30$

$\sf \implies 5x = 20$

Divide both sides by 5.

$\implies \sf \dfrac{5x}{5} = {20}{5}$

$\implies \sf x=4$

>> Age of second child = x + 3 = 4 + 3 = 7 years.

>> Age of third child = x + 6 = 10 years.

>> Age of fourth child = x + 9 = 4 + 9 = 13 years.

>> Age of fourth child = x + 12 = 4 + 12 = 16 years.