Question

The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?


for 93 points​

Answer 1

$<b>Answer </b>$: 4

$<b>Explanation:</b>$

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

→ 5x = 20

→ x = 4.

$<b>$Age of the youngest child → x = 4 years.

Answer 2

Given : Number of children = 5

Sum of ages =50 years

Time difference between each child birth =3 years

Solution :-

Let the ages of the children be -

x, x+3 , x+6 , x+9 and x+12 (as there is the difference of 3 years between each child)

A/Q

x+x+3+x+6+x+9+x+12 =50

5x + 30=50

5x =50-30

5x =20

x=20/5

x=4

So the ages are -

x=4 years

x+3 =4+3

=7 years

x+6 =4+6

=10 years

x+9 =4+9

=13 years

and x+12 =4+12

=16 years

Thus the age of the youngest child is 4 years.