Question

the sum of ages of a ,b and c is 81 years,one year before the ratio of ages of a and b was 1:2 and that of b and c was 4:7 ,so find the age of b after 6 years
ans-31 plz tell solution​

Answer 1

Answer:

Ageof A, 4 year hence is equal to age of B, 1 year ago and ratio of present age of A ... Find the difference of age of B and D. ... B's age was 10 times of C's age 10 years

Answer 2

Answer:

The sum of a,b and c before one year=81-1×3=78.

Since before one year, the ratio of ages of a and b is 1:2 and that of b and c is 4:7.

So, the ratio of ages of a,b and c=2:4:7.

Hence, let 2k,4k,7k be the ages of a,b and c respectively.

According to the question,

2k+4k+7k=78

or, 13k=78

or, k=6.

Hence, the age of b is 6×4=24 years.But this age is one year less than his present age.So, his present age is 25 years.And his age after 6 years will be 31 years.