The sum of ages of A, B, and C is 93 yr. Ten years ago, the ratio of their age was 2:3:4, Find the present age of A.?
Answers
Answer:
Present age of A is 24 years.
Step-by-step explanation:
Question says that,
The sum of the age of A, B, and C is 93 years.
Ten years ago the age of A, B, and C was 2 : 3 : 4.
Find the present age of A.
Suppose, ten years ago the age of :
- A = years.
- B = years.
- C = years.
Therefore, their present age will be :
- A = years.
- B = years.
- C = years.
Given :
Solving for
Hence, the present age of A is :
Topic:
Ratio and proportion
Question:
The sum of ages of A, B, and C is 93 years . Ten years ago, the ratio of their age was 2:3:4 . Find the present age of A ?
Given:
- The sum of ages of A, B, and C is 93 years.
- The ratio of their ages 10 years ago which was 2:3:4.
To Find:
- The present age of A.
Solution:
Let x be their present age,
The ratio will be 2x : 3x : 4x
Now the ratio of the present age would be their ages ten years ago plus 10. So the ratio of their present age will be
➙ 2x + 10 : 3x + 10 : 4x + 10
We also know the sum of their present age which is 93 years . So according to the information we got,
➙ 2x + 10 + 3x + 10 + 4x + 10 ➞ 93
➙ 2x + 3x + 4x + 10 + 10 + 10 ➞ 93
➙ 9x + 30 ➞ 93
➙ 9x ➞ 93 - 30
➙ 9x ➞ 63
➙ x ➞ 63/9
➙ x ➞ 7
Thus, we got the value of the constant multiplying factor .
Now,
So , the age of A ten years back is
➞ 2x
➞ 2 × 7
➞ 14
The age of B ten years back is
➞ 3x
➞ 3 × 7
➞ 21
The age of C ten years back is
➞ 4x
➞ 4 × 7
➞ 28
The final results,
The present age of A is
➠ 14 + 10
➠ 24
The present age of B is
➠ 21 + 10
➠ 31
The present age of C is
➠ 28 + 10
➠ 38
Hence, we got the present age of A which is 24 .