The sum of ages of A B and C is 96 yeras two years hence the ratio between ages of A and B will be 5:7 and the ratio between C's age one year before and B's age after one year will be 17:9. Find A's age after 8 years
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Answer:
26 Years
Step-by-step explanation:
Let say A's Age = A Years
& B's Age = B Years
Then C's Age = 96 - (A + B)
two years hence the ratio between ages of A and B will be 5:7
=> (A+ 2)/(B+ 2) = 5/7
=> 7A + 14 = 5B + 10
=> 5B = 7A + 4 Eq1
ratio between C's age one year before and B's age after one year will be 17:9
=> (96 - (A + B) - 1) /(B + 1) = 17/9
=> 9 ( 95 - (A + B)) = 17(B + 1)
=> 855 - 9A - 9B = 17B + 17
=> 26B = 838 - 9A Eq1
26*eq 1 = 5 * eq2
=> 26(7A + 4) = 5(838 - 9A)
=> 182A + 104 = 4190 - 45A
=> 227A = 4086
=> A = 18
A's Present age = 18 Years
A's age after 8 years = 18 + 8 = 26 Years
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