Question

The sum of ages of a father and his son is 45 years. Five years ago, the product of their ages was four times the father's age at that time. The present age of the father is

Answer 1

Hope the answer is clear. Please mark me as brainliest.

Answer 2

hey there !!

Let sons age be = x years. Then fathers age = (45 - x)years. 

now ,

According to the question:-

five years ago , the product of their ages was four times the father's age at that time ,

therefore. ,

(x—5)(45—x—5) = 4(45- x - 5)

hence (x—5) = 4 so x = 9 years

and , the age of father = 45-9 = 36 years

Their ages are 36 years and 9 years

hope it helps ,!!