Math, asked by susantagiri100685, 2 months ago

the sum of ages of a man and his son is 45 years. Five yearsago, the product of their age was four times the man's age at the time. Find their present ages.​

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Answers

Answered by visankreddy
1

Step-by-step explanation:

Let the 'x' years be the present age of the son

Given: sum of present ages of man and his son is 45 years.

Man's present age = (45-x)years

Five years ago :

Man's age = (45-x-5) = (40 - x) years

son's age = (x - 5)years

A.T.Q

Product of their ages was four times the man's age at the time.

(40 - x)(x - 5) = 4(40 - x)

x - 5 = 4

[(40 - x) got cancelled]

x = 4 + 5

x = 9 years

Son's present age = x = 9 years

Man's present age = (45-x) years = (45 - 9) years = 36 years

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