Question

The sum of ages of a man and his son is 45 years. Five years ago, the product of their ages was four times the man's age at the time. Find their present ages.

Answer 1

SOLUTION :  

Let the ‘x’ years be the present age of the son  

Given : sum of present ages of man and his son is 45 years.

Man’s present age = (45 – x)years

Five years ago :  

Man’s age = (45 – x - 5) = (40 - x) years

son’s age = (x - 5)years

A.T.Q

Product of their ages was four times the man’s age at the time.

(40 – x) (x – 5) = 4(40 – x)

x – 5 = 4

[(40 – x) got cancelled]

x = 4 + 5  

x = 9 years

Son’s present age = x = 9 years

Man’s present age = (45 – x) years = (45 – 9) years = 36 years

Hence, Son’s present age = 9 years and Man’s present age = 36 years  

HOPE THIS ANSWER WILL HELP YOU….

Answer 2

Answer:

Man age=36 boys age=9

Step-by-step explanation:

1.Let Man's past age=M

Son's past age=S

2.according to question M*S=M*4

Therefore,S=4

3.Son's current age=4+5=9

Father's current age=45-9=36(since,sum of father's current age and son's current age=45)