Question

the sum of ages of a man and his son is 59 years 3 years hence the numerocal poduct of their ages will be 750 find their present ages​

Answer 1

Step-by-step explanation:

let the age of father be x and boy be y .

x+y = 59

x = 59-y

(x +3 )(y+3 ) = 750 .

(59 -y +3)(y+3) = 750

62 -y × y+3

62y -y² + 186 -3y = 750

y² - 59y +564

y² -12y - 47y +564 = 0

y(y-12) - 47( y-12)

y = 12 or 47

Son cannot be 47 years so son's age is 12 years .

Father will be 47 years