Question

The sum of ages of a son and a father os 56 years old. After 4 years, Athe age of the father will be three times that of her son. Find their ages? please guys answer fast​

Answer 1

Answer:

hope it help you amigo

A) 12 years, 44 years

Step-by-step explanation:

Let x be the present age of the son.

So father's age will be 56-x

After 4 years the age of the father will be 3 times that of his son

(56−x+4)=3(x+4)(56−x+4)=3(x+4)

56−x−3x−12+4=056−x−3x−12+4=0

4x = 56 -8 = 48

x = 12

The age of the son is 12 years.

The age of his father is 44 years.

Answer 2

❥${\underline{\underline{\large{\mathtt{ANSWER:-}}}}}$

Father's age is 44 years and son's age is 12 years.

❥${\underline{\underline{\large{\mathtt{EXPLANATION:-}}}}}$

•Given:-

• Sum of son's and father's ages = 56 years.
• After 4 years, the age of the father will be three times that of his son.

•To find:-

• Father's age and son's age.

•Solution:-

Let father's age be x years and son's age be y years.

According to the question,

x + y = 56

→ x = 56 - y ..............(i)

$\sf{After\:4\: years,\:son's\:age=(y+4)\: years}$

$\sf{After\:4\: years,\: father's\:age=(x+4)\: years}$

★After 4 years, father's age will be 3 times of his son's age.

According to the question,

$\sf{x+4\:=3(y+4)}$

$\implies\sf{x+4\:=3y+12}$

† putting x = (56-y) from eq.1†

$\implies\sf{(56-y)+4\:=3y+12}$

$\implies\sf{56-y+4\:=3y+12}$

$\implies\sf{-y-3y\:=12-56-4}$

$\implies\sf{-4y\:=-48}$

$\implies\sf{y\:=12}$

Son's age = 12 years.

★Now find father's age.

Taking eq(i)

x = 56 - y

→ x = 56-12

→ x = 44

Father's age = 44 years.