Question

the sum of ages of athe sum of Ages of a man and his son is 45 years five years ago the product of their ages in years was four times the man's age find their present ages ​

Answer 1

Answer:

Let the age of father be x years and age of his son be ( 45 - x ) years,

Five years ago,

Age of father = ( x - 5 ) years

Age of his son = ( 45 - x - 5 ) years = ( 40 - x ) years

According to the question,

Product of their ages five years ago = 4 × father's age five years ago

=> ( x - 5 ) ( 40 - x ) = 4( x - 5 )

= > \cancel{(x - 5)}(40 - x) = 4 \cancel{(x - 5)}=>

(x−5)

(40−x)=4

(x−5)

=> 40 - x = 4

=> 40 - 4 = x

=> 36 = x

Hence,

Present age of father = x years = 36 years

Present age of his son = ( 45 - x ) = ( 45 - 36 ) = 9 years

\:

Answer 2

Answer:

The age of father is 36 years

The age of son is 9 years

Step-by-step explanation:

Let the age of father be x

then, the age of son will be (45 - x)

Five years ago,

(x-5)(40-x) = 4(x-5)

40 - x = 4

x = 36