Question

the sum of Ages of Bharath and Sharad is twice the sum of their age 7 years ago what is the product of their present age if the sum of the square of their age is 400

Answer 1

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Answer 2

The product of their present age = 192

To find:

the product of their present age

Given data:

the sum of Ages of Bharath and Sharad is twice the sum of their age 7 years ago

the sum of the square of their age = 400

Solution:

let bharath = B

      sharad = S

B + S = 2[B + S - 14]

B + S = 2B + 2S - 28

B + S = 28

the sum of the square of their age = 400

that is  $(S+B)^{2}=400$

we know $(S+B)^{2}=S^{2}+B^{2}+2 S B$

substituting in the above equation we get,

$(28)^{2}= 400 +2 S B$

$784= 400 + 2 S B$

$784 - 400= 2 S B$

2SB = 384

SB = 192

To solve more:

1. A man's age is 4 times the sum of the ages of three children in 8 years he will be twice the sum of their ages what is the man's age​

https://brainly.in/question/12707903

2. The sum of ages of husband and his wife is four times the sum of ages of their children.four year ago, the ratio of sum of their ages to the sum of sum of ages of their children was 18:1.two year hence the ration will be3:1 how many children do they have?

https://brainly.in/question/207222