The sum of ages of Father and his son is 45 years. 5 years ago, the product of their ages was 124. Determine present ages.
Answers
Given,
Sum of ages of a father and his son = 45 years....(i)
Five years ago, product of their ages = 124 years....(ii)
Let,
Present age of father = x years
Present age of son = (45−x) years(By using (i))
Now, forming a quadratic equation,
⇒(x−5)(45−x−5)=124(By using (ii))
⇒(x−5)(40−x)=124
⇒40x−x
2
−200+5x=124
⇒x
2
−45x+324=0
Step 2: Solve the equation using middle term split method.
⇒x
2
−36x−9x−324=0
⇒(x−36)(x−9)=0
⇒x=36,9
Clearly, x cannot be 9,∵ the age of father cannot be less than his son’s age.
∴Present age of father, x=36 years
and, present age of son, (45−x)=9 years
Hence, the present age of father is 36 years and his son is 9 years.
HOPE IT WILL HELP YOU...
⇒ Question:
⇒ The sum of the ages of the Father and his son is 45 years. 5 years ago, the product of their age was 124. Determine present ages.
==============================================================
→→ Answer:
Step 1: Form a quadratic equation according to the given conditions.
Given,
The sum of ages of a father and his son = 45 years....(i)
Five years ago, product of their ages = 124 years....(ii)
Let,
The present age of the father = x years
The present age of the son = (45−x) years (By using (i))
Now, forming a quadratic equation,
⇒(x−5)(45−x−5)=124 (By using (ii))
⇒(x−5)(40−x)=124
⇒40x−x²−200+5x=124
⇒x²−45x+324=0
Step 2: Solve the equation using the middle-term split method.
⇒x²−36x−9x−324=0
⇒(x−36)(x−9)=0
⇒x=36,9
Clearly, x cannot be 9,∵ the age of a father cannot be less than his son’s age.
∴The present age of the father, x=36 years, and, the present age of the son, (45−x)=9 years
Hence, the present age of the father is 36 years and his son is 9 years.
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