Question

the sum of Ages of father and his son is 45 years five years ago the product of their ages was 124 years find their present ages

Answer 1

let the Age of father = x
the Age of son = 45 - x

Five years ago

Age of father = x - 5 years
Age of son = 45 - x - 5 years
= 40 - x years

Now (x-5)(40-x) = 124

40x- x² +5x - 200 = 124

45x - x² = 324

x² -45x + 324 = 0

x² - (36+9)x + 324

x² - 36x - 9x + 324

x ( x - 36 ) + 9 (x - 36)

(x +9) (x- 36) = 0

x = -9 or x = 36

Age can't be negative so

Age of father = 36 years

Age of son = 45-36 = 9
years

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Answer 2

Answer:

let the Age of father = x

the Age of son = 45 - x

Five years ago

Age of father = x - 5 years

Age of son = 45 - x - 5 years

= 40 - x years

Now (x-5)(40-x) = 124

40x- x² +5x - 200 = 124

45x - x² = 324

x² -45x + 324 = 0

x² - (36+9)x + 324

x² - 36x - 9x + 324

x ( x - 36 ) + 9 (x - 36)

(x +9) (x- 36) = 0

x = -9 or x = 36

Age can't be negative so

Age of father = 36 years

Age of son = 45-36 = 9

years

Hope you like it

Thanks