Math, asked by Anonymous, 15 hours ago

The sum of ages of father and his son is 45 yrs.five yrs ago,the product of their ages was 124. Determine their present ages .

Answers

Answered by tname3345
5

Step-by-step explanation:

given :

  • sum of ages of father of her son = 45 year

  • product of their ages = 124

to find :

  • what is her present age = ?

  • what is her present age = ?

solution :

thier age = 124 first we will simplify the

124

  • age = (x - 5) x (y-5) = 124

  • age = (45-y-5) x(y – 5) = 124

  • age = 40y-y² - 200 + 5y = 124

  • age = y²-45y + 324 = 0

  • age = y²-36y - 9y+ 324 = 0

  • age = (y - 36)-9 (y - 36) = 0

  • age = (y - 36) (y - 9) = 0

  • age = 36

we substitute them

age = 45

  • age = 45

  • age = 45 - 9

  • age = 36

age of father = 36

age of son = 9 years

Answered by itzsehaj
22

QUESTION:-

The sum of ages of father and his son is 45 yrs. Five yrs ago, the product of their ages was 124. Determine their present ages .

GIVEN:-

  • The sum of the ages of father and his son is 45 years .
  • 5 years ago the product of their ages was 124.

TO FIND:-

  • Their Present Ages.

SOLUTION :-

  • Let the present age of father be x years
  • And the present age of son be y years .

According to the Question,

x + y = 45  

Five years ago, the product of their ages was 124.

(x - 5) * (y - 5) = 124\\= (45 - y - 5) *(y - 5) = 124  \\= 40y - y² - 200 + 5y = 124  \\= y²  - 45y  + 324 = 0 \\ = y²  - 36y  - 9y + 324 = 0\\=y (y - 36) - 9 (y - 36) = 0\\= (y - 36) (y - 9) = 0\\= y = 36 or y = 9  

Putting y value in Equation

x + y = 45x + 9 = 45x = 45 - 9x = 36

  • The present age of father = 36 years
  • The present age of son = 9 years.

Hence, the present age of father be 36 years and The present age of son is 9 years.

           Hope it helps :D

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