The sum of ages of father and his son is 45 yrs.five yrs ago,the product of their ages was 124. Determine their present ages .
Answers
Answered by
5
Step-by-step explanation:
given :
- sum of ages of father of her son = 45 year
- product of their ages = 124
to find :
- what is her present age = ?
- what is her present age = ?
solution :
thier age = 124 first we will simplify the
124
- age = (x - 5) x (y-5) = 124
- age = (45-y-5) x(y – 5) = 124
- age = 40y-y² - 200 + 5y = 124
- age = y²-45y + 324 = 0
- age = y²-36y - 9y+ 324 = 0
- age = (y - 36)-9 (y - 36) = 0
- age = (y - 36) (y - 9) = 0
- age = 36
we substitute them
age = 45
- age = 45
- age = 45 - 9
- age = 36
age of father = 36
age of son = 9 years
Answered by
22
QUESTION:-
The sum of ages of father and his son is 45 yrs. Five yrs ago, the product of their ages was 124. Determine their present ages .
GIVEN:-
- The sum of the ages of father and his son is 45 years .
- 5 years ago the product of their ages was 124.
TO FIND:-
- Their Present Ages.
SOLUTION :-
- Let the present age of father be x years
- And the present age of son be y years .
According to the Question,
x + y = 45
Five years ago, the product of their ages was 124.
Putting y value in Equation
- The present age of father = 36 years
- The present age of son = 9 years.
Hence, the present age of father be 36 years and The present age of son is 9 years.
Hope it helps :D
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