The sum of ages of father and his son is 54 years. 3 years earlier, the father's age was thrice that
of his son's age. Find the present ages of both.
Answers
Answered by
2
Answer:
Let present age of father and son be x and y respectively
then 3 years ago sum of then age is 40.
⇒(x−3)+(y−3)=40
x+y=46⇒y=46−x...(1)
After 2 years ; sum of age of father and son is
Let t=(x+2)+(y+2)
t=(x+2+46−x+2) from (1)
=46+4
t=50
So sum of their ages after 2 years = 50.
Answered By ansh
Answered by
2
Answer:
the age of son is 17 and the age of father is 54-17=37
Step-by-step explanation:
according to the question,
3x+3=54
so,
3x=54-3
3x=51
x=51/3
x=17
therefore, age of son is 17 years and the age of father is 54-17=37 years
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