The sum of ages of father and son is 104 .Father told to his son when i was at your age at that time your age was one fourth of my present age .Find their ages?
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Let the age of father be 'x'
And the age of son be 'y'
So, x+y=104
Now,
According to the question ,
x=1/4y
So, putting x=1/4y in x+y=104 , we get
y = (104×4) ÷ 5
y = 83.2
i.e. Father's age is 83 years 2 months.
And son's age is = (104 - 83.2)
i.e. 20 years 8 months.
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