Question

The sum of ages of four people in a room is 46years.the sum of their ages 4years ago was how much?

Answer 1

Step-by-step explanation:

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Answer 2

Given,

Sum of ages of four people = 46 years

To find,

Sum of their ages 4 years ago

Solution,

Let the ages of four people be:

Let the age of first person be  a.

Let the age of second person be b.

Let the age of third person be c.

Let the age of fourth person be d.

Given that, a+b+c+d = 46 years.

Age of them 4 years ago would be:

Then first person's age= a-4

Then second person's age= b-4

Then third person's age= c-4

Then fourth person's age= d-4

Sum of their ages 4 years ago = (a-4) + (b-4) + (c-4) + (d-4)

= a+b+c+d-16

We know that a+b+c+d = 46

= 46-16

= 30

Hence,sum of their ages 4 years ago would be 30.