Question

The sum of ages of madhan and Mohan is 16 years. Four years ago madhan was 3times old as Mohan. Find the present ages.

Answer 1

Answer:

Step-by-step explanation:

Let the age of Madhan and Mohan be x and y respectively.

According to question, x + y = 16    ---- (1)

Also, x-4 = 3(y-4)

=> x= 3y-8

Putting this in (1),

4y = 24

=> y = 6

x= 3X6-8 = 10

 Therefore, their present ages are 10 and 6 respectively

Answer 2

Answer :

• Madhan's present age = 10 years
• Mohan's present age = 6 years

Step-by-step explanation :

Given,

• The sum of ages of Madhan and Mohan is 16 years
• Four years ago Madhan was 3 times old as Mohan.

To find,

• The present age of Madhan
• The present age of Mohan

Solution,

      Let the present age of Madhan be x years

Since,  Madhan's age + Mohan's age = 16 years

                      x      +    Mohan's age = 16 years

                         Mohan's age = (16 - x) years

Four years ago,

Madhan's age = (x - 4) years

Mohan's age = (16 - x - 4) years

                       = (12 - x) years

As given,

     Madhan's age = 3 × (Mohan's age)

              x - 4   =   3(12 - x)

              x - 4   =   36 - 3x

               3x + x = 36 + 4

                 4x = 40

                   x = 40/4

                   x = 10

=> 16 - x = 16 - 10 = 6

∴ The present age of

• Madhan = 10 years

• Mohan = 6 years