Question

The sum of ages of mother and daughter is 65 years. 10 years ago the product of their ages was 5 times the age of mother at that time. Then find the ratio of the present age of mother to the present age of daughter (age of mother is greater than 30 years)

Answer 1

Answer:

Hence the ratio of present age is $\frac{10}{3}$

Step-by-step explanation:

Let

present age of mother$=x$

present age of daughter=$=y$

From question

$x+y=65$-----------(1)

10 years ago

Mother's age$=(x-10)$

Daughter's age$=(y-10)$

From question

$(x-10)(y-10)=5(x-10)$

⇒$\frac{(x-10)}{(x-10)} (y-10)=5\frac{(x-10)}{(x-10)}$

⇒$y-10=5$

⇒$y-10+10=5+10$

⇒y=15

Substitute the value of y in the equation (1).

$x+y=65$

⇒$x+15=65$

⇒$x+15-15=65-15$

⇒$x=50$

Now, the ratio of the present age of mother to the present age of daughter is,

Present age of mother/present age of daughter$=\frac{50}{15} =\frac{10}{3}$

Answer 2

Answer:

I aslo don't know pls say or answer to this question

Step-by-step explanation:

Sum of the ages of a mother and her daughter is 65 years five years ago the product of their ages in here was 700 find the present age of the mother and daughter