Question

the sum of ages of sarmad and his brother is 38. 7 years ago, sarmad was thrice as old as his brother. find his present age

Answer 1

Answer:

Fahad = x

Ahmad=y

Fahad seven years ago = x-7

Ahmad seven years ago = y-7

x+y=38 OR y=38-x

Seven years ago:

(x-7)=3(y-7)

x-7=3y-21

x+14=3y

Substitute 38-x for y

x+14=3(38-x)

x+14=114-3x

add 3x-14 to both sides

4x=100

x=25

so y=13

This is correct because 7 years ago Fahad was 18 and ahmad was 6

Answer 2

Answer:

9.675 of sarmad

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