The sum of
ages of son and father is 56 years. After four years the age of
the father will be thrice the son's age. Find their ages.
Answers
Answered by
3
Step-by-step explanation:
s+f =56
f=56-s
f+4 =3(s+4)
f+4 = 3s+12
56-s +4 = 3s+12
60-12 = 4s
s = 48/4 = 12
f= 56-12 = 44
Answered by
2
Let the son age after 4 years be x+4
Then father’s age after four year be 3x+4
X+4+3x+4=56
4x+8=56
4x=56-8
4x=48
X=48/4
X=12
Father’s present age = 3x=3*12=36
Son’s present age =x=12
Then father’s age after four year be 3x+4
X+4+3x+4=56
4x+8=56
4x=56-8
4x=48
X=48/4
X=12
Father’s present age = 3x=3*12=36
Son’s present age =x=12
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