Question

the sum of Ages of subbu and Tobu is 18 years and the difference between their ages is 4 years find the ages of subbu and Tobu ​

Answer 1

Answer:

Tobu is 7 years old and Subbu is 11 years.

Step-by-step explanation:

Given :

Sum of their ages = 18

Difference between the ages = 4

To find :

Their ages

Solution :

Let the ages be -

• Subbu as x
• Tobu as (18 - x)

Difference between their ages = 4

$\longrightarrow$ x - (18 - x) = 4

$\longrightarrow$ x - 18 + x = 4

$\longrightarrow$ 2x - 18 = 4

$\longrightarrow$ 2x = 4 + 18

$\longrightarrow$ 2x = 22

$\longrightarrow$ x = 22/2

$\longrightarrow$ x = 11

Subbu's present age = 11 years

$\rule{300}{1.5}$

★ Value of (18 - x)

$\longrightarrow$ 18 - 11

$\longrightarrow$ 7

Tobu's present age = 7 years

$\therefore$ Tobu is 7 years old and Subbu is 11 years.

Answer 2

Let the age of subbu be x.

And the age of Tobu be y.

Given :

x + y = 18 -----------(I)

x - y = 4 -----------(II)

On adding equation (I) and (II), we get

==> x + y + x - y = 18 + 4

➡ 2x= 22

➡ x = 22/2

➡ x = 11

$\rule{300}{1.5}$

Put the value of x in equation (I)

➡x + y = 18

➡11 + y = 18

➡ y = 18-11

➡ y = 7

.°. The age of subbu = x = 11 years.

And the age of Tobu = y = 7 years.