Math, asked by InfoTechFactz, 9 months ago

The sum of ages of the father and the son is 48 yeas. The quotient

obtained by dividing the age of the son by the age of the father is 1

5

.

Find their ages.

Answers

Answered by MysteriousAryan

Answer:

let father's age be X

SONS AGE BE Y

X/Y=1/5

BY CROSS MULTIPLICATION

5X=Y

SUM OF AGES =48

X+Y =48

PUT VALUE OF Y

Step-by-step explanation:

6X =48

X =8

Y =40

HOPE IT HELPS PLEASE MARK AS BRAINLIEST

I THINK YOUR QUESTION IS WRONG BECAUSE BECAUSE FATHER'S AGE IS LESS THAN THE SUN AGE PLEASE CHECK IF THE FRACTION IS 5 BY 1 AUR 1 BY 5

Answered by yuvraj99975

$\Huge\fbox{\color{red}{Answer}}$

Correct Question:- The sum of the age of father and the son is 48 year . the quotient obtained by dividing the age of son by the age of father is 1/ 5 .find their ages.

Solution:- Let the age of father = x years

Age of son = (48-x) years

According to Question,

$\frac{48-x}{x}= \frac{1}{5}$

5×(48-x) = x

240-5x=x

240=x+5x

240=6x

x= $\frac{240}{6}$

$\therefore x=40$

Now,age of father = x = 40 years

Age of son = (48-x) years

= 48-40 years

= 8 years

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$\mathbb{MARK \: IT \: AS \: BRAINLIEST}$

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The sum of ages of the father and the son is 48 yeas. The quotient obtained by dividing the age of the son by the age of the father is 15. Find their ages.​

Answers

let father's age be X

HOPE IT HELPS PLEASE MARK AS BRAINLIEST

The sum of ages of the father and the son is 48 yeas. The quotient

obtained by dividing the age of the son by the age of the father is 1

5

.

Find their ages.