Question

the sum of ages of two brothers is 25 years and their difference is 3 years.Find their ages

Answer 1

let elder one be x and younger y
x+y=25
=x=25-y

x-y=3
=x=y+3
since x is same,
25-y=y+3
2y=22
y=11
x-y=3
x-11=3
x=14
thus elder one's age is 14 and younger one's is 11!!

hope this helps you!!:)

Answer 2

Answer:

x=14 and y=11

Step-by-step explanation:

let the two brother present ages be x and y

x + y=25

x - y=3  

on adding both the equations

2x=28

X=14 years

Substituting in equation 1

14+y=25

Y=11 years