Question

The sum of all 3 digit numbers each of which on division by 5 leaves remainder 3 is

Answer 1

smallest 3 digit number which leave the remainder 3 when divided by 5 =103
largest 3 digit number which leave the remainder 3 when divided by 5 =998
3 digit number after 103 which leave the remainder 3 when divided by 5 =108
an ap is formed: 103,108........998
first term=103
common difference=5
let the total no. of three digit numbers which leave the remainder 3 when divided by 5=n
998=103+(n-1)5
180=n
sum of ap=180/2 *(103+998)=90*1101
=99090
Hope this will help you.. ✌