The sum of all 4 digited numbers that can be formed by taking the digits from 0,1,3,5,7,9 without repition no spam ill report all their questions if answered correctly ill give 10 thanks and follow them
Answers
✍︎......︎︎︎ᴥ︎︎︎︎︎︎ Aɴsᴡᴇʀ࿐
Total no. of digits are 5, i.e., n=5
Total no. of digits required is 4, i.e.,
r = 4
Therefore,
No. of 4 digits no. that can be formed =nPr=5P4=1!5!=120
No. of times each digit will appear =5120=24
Sum of digits at unit place =24(1+3+5+7+9)=24×25=600
Sum of all numbers =600×1000+600×100+600×10+600=666600
Hence the sum off all 4 diit numbers is 666600.
P.S: As 0 has no Value so I didn't mention it.
H O P E I T H E L P S !!!
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Answer:
hello bro
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so only
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I think u will understand me that is my mistake
hereafter I won't disturb u bro...I wish that u were my own brother but u...
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kindly report this answer too