Math, asked by Anonymous, 5 months ago

The sum of all 4 digited numbers that can be formed by taking the digits from 0,1,3,5,7,9 without repition no spam ill report all their questions​. if answered correctly ill give 20 thanks and follow them​.Plese answer in step by step explaination clearly​

Answers

Answered by Anonymous
17

Answer:

Total no. of digits are 5, i.e.,

n=5

Total no. of digits required is 4, i.e.,

r=4

Therefore,

No. of 4 digits no. that can be formed =nPr=5P4=1!5!=120

No. of times each digit will appear =5120=24

Sum of digits at unit place =24(1+3+5+7+9)=24×25=600

Sum of all numbers =600×1000+600×100+600×10+600=666600

Hence the sum off all 4 diit numbers is 666600.

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Answered by sofia2647
3

Answer:

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