Question

the sum of all angles of a regular polygon is 2880 .what is the number of sides of the polygon ? what is one outer angle ? what is one inner angle of the polygon ? please send the correct answer very argent ​

Answer 1

Answer:

let the polygon have s sides

value of one inner angle= 2880/s

the value of one external angle =180 - 2880/s

the sum of all external angle = (180 - 2880/s)×s

= 360

After simplification

180s - 2880 = 360

180s = 360 + 2880 = 3240

s = 3240/180 = 18

So polygon has 18 sides and one

Inner angle = 2880/18 = 160

one outer angle = 180 - 160 = 20