Question

The sum of all edges of a cubiod is 40cm.The length of the longest rod that can kept inside the box is√38 cm.Then the total surface area is??​

Answer 1

Answer:

l + b + h = 40

√l² + b² + h² = √38

l²+b²+h² = 38

(l+b+h)² = l²+b²+h²+2(lb+bh+lh)

1600 = 38 + 2(lb+bh+lh)

1600 - 38 = 2(lb+bh+lh)

1562 = 2(lb+bh+lh)

T.S.A = 2(lb+bh+lh)

then,

1562cm² = T.S.A of cuboid