the sum of all even integers between 1 and 100 is 2550 ,then sum of all odd integers between 50 &150 ???
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The sum of the first n odd numbers is n^2, where n is the number of terms.
In this case, we can find the sum of all odd integers between 50 and 150 can be calculated as the difference between the first n odd integers up to 150 and 50.
An odd integer is given by the term, 2n-1.
So, when 2n-1 = 49, we can find the value of n.
2n = 49 + 1 = 50. Thus, n = 50/2 = 25.
Therefore, the sum of 25 odd numbers, till 49 = 25^2.
Similarly, equating 2n - 1 = 149, we get the value of n = (149+1)/2 = 150/2 = 75.
So, the sum of first 75 odd numbers, till 149 = 75^2.
Thus, the sum of odd numbers between 50 and 150 is the difference of 75^2 and 25^2.
75^2 - 25^2 = (75+25) * (75-25)
= 100 * 50
= 5000.
Thus, the sum of the odd numbers between 50 and 150 is 5000.
In this case, we can find the sum of all odd integers between 50 and 150 can be calculated as the difference between the first n odd integers up to 150 and 50.
An odd integer is given by the term, 2n-1.
So, when 2n-1 = 49, we can find the value of n.
2n = 49 + 1 = 50. Thus, n = 50/2 = 25.
Therefore, the sum of 25 odd numbers, till 49 = 25^2.
Similarly, equating 2n - 1 = 149, we get the value of n = (149+1)/2 = 150/2 = 75.
So, the sum of first 75 odd numbers, till 149 = 75^2.
Thus, the sum of odd numbers between 50 and 150 is the difference of 75^2 and 25^2.
75^2 - 25^2 = (75+25) * (75-25)
= 100 * 50
= 5000.
Thus, the sum of the odd numbers between 50 and 150 is 5000.
vamshikrishna1:
sir the answer is 2550
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