the sum of all even numbers from 1 to 300
Answers
Answer:
Therefore, 90300 is the sum of first 300 even numbers.
Step-by-step explanation:
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Answer:even numbers = 2,4,6,8…..300
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression with
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2common difference = d = 2
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2common difference = d = 2Total no. of terms = n = unknown
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2common difference = d = 2Total no. of terms = n = unknownnth term = a +(n-1)d
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2common difference = d = 2Total no. of terms = n = unknownnth term = a +(n-1)dtherefore
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2common difference = d = 2Total no. of terms = n = unknownnth term = a +(n-1)dthereforea +(n-1)d = 300
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2common difference = d = 2Total no. of terms = n = unknownnth term = a +(n-1)dthereforea +(n-1)d = 3002 +(n-1)2 = 300
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2common difference = d = 2Total no. of terms = n = unknownnth term = a +(n-1)dthereforea +(n-1)d = 3002 +(n-1)2 = 300solving this equation
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2common difference = d = 2Total no. of terms = n = unknownnth term = a +(n-1)dthereforea +(n-1)d = 3002 +(n-1)2 = 300solving this equationn = 150
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2common difference = d = 2Total no. of terms = n = unknownnth term = a +(n-1)dthereforea +(n-1)d = 3002 +(n-1)2 = 300solving this equationn = 150.
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2common difference = d = 2Total no. of terms = n = unknownnth term = a +(n-1)dthereforea +(n-1)d = 3002 +(n-1)2 = 300solving this equationn = 150.Sum
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2common difference = d = 2Total no. of terms = n = unknownnth term = a +(n-1)dthereforea +(n-1)d = 3002 +(n-1)2 = 300solving this equationn = 150.Sum= n/2 [ 2a +(n-1)d]
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2common difference = d = 2Total no. of terms = n = unknownnth term = a +(n-1)dthereforea +(n-1)d = 3002 +(n-1)2 = 300solving this equationn = 150.Sum= n/2 [ 2a +(n-1)d]=150/2 [ (2x2) +(150-1)2]
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2common difference = d = 2Total no. of terms = n = unknownnth term = a +(n-1)dthereforea +(n-1)d = 3002 +(n-1)2 = 300solving this equationn = 150.Sum= n/2 [ 2a +(n-1)d]=150/2 [ (2x2) +(150-1)2]= 75 x 302
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2common difference = d = 2Total no. of terms = n = unknownnth term = a +(n-1)dthereforea +(n-1)d = 3002 +(n-1)2 = 300solving this equationn = 150.Sum= n/2 [ 2a +(n-1)d]=150/2 [ (2x2) +(150-1)2]= 75 x 302= 22650
even numbers = 2,4,6,8…..300the above series is an Arithmetic Progression withfirst term = a = 2common difference = d = 2Total no. of terms = n = unknownnth term = a +(n-1)dthereforea +(n-1)d = 3002 +(n-1)2 = 300solving this equationn = 150.Sum= n/2 [ 2a +(n-1)d]=150/2 [ (2x2) +(150-1)2]= 75 x 302= 22650sum of all even numbers upto 300 = 22650
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