Question

the sum of all integers lying between 2 and 200 which are divisible by 3 is​

Answer 1

Answer:

3,6,9,......198

Q

198=3+(n-1)3

195/3=n-1

65=n-1

n=66

S=n/2(2a+(n-1)d)

=66/2(2(3)+(66-1)3)

33(6+195)

6633

Answer 2

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