Math, asked by abhinav3513, 11 months ago

The sum of all natural numbers between 500 and 1000 which are divisible by 13 is
(a) 28,405
(b) 24,805
(c) 28,540
(d) none

Give proper explanation

Answers

Answered by kunal221922
9

smallest number divisible by 13 is 507

Biggest number divisible by 13 is 988

Now Using AP formula

t=a+(n-1)d

t=988 a=507 d=13

988=507+(n-1)13

481=13n-13

n=494/13

n=38

Using AP sum formula

Sum =n/2 (a+t)

sum=38/2 (507+988)

sum=19×1495

Sum =28405

Option A

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