Math, asked by ashrar64, 5 months ago

the sum of all natural numbers from 1 to 100 is​

Answers

Answered by kartik2507
3

Answer:

5050

Step-by-step explanation:

a = 1 d = 1

number of terms An

An = a + (n-1)d

100 = 1 + (n-1)1

100 = 1 + n - 1

n = 100

Sum of 100 terms

sn =  \frac{n}{2} (2a + (n - 1)d) \\  =  \frac{100}{2} (2(1) + (100 - 1)(1) \\ =  50(2 + 99) \\  = 50 \times 101 \\  = 5050

Sum of all natural numbers from 1 to 100 = 5050

Hope you get your answer

Answered by mondalsourima283
1

Answer:

5050

Step-by-step explanation:

n(n+1)/2

=100(100+1)/2

=100(101)/2

=10100/2

=5050

Similar questions
Math, 10 months ago