Question

the sum of all natural numbers from 1 to 100 is​

Answer 1

Answer:

5050

Step-by-step explanation:

a = 1 d = 1

number of terms An

An = a + (n-1)d

100 = 1 + (n-1)1

100 = 1 + n - 1

n = 100

Sum of 100 terms

$sn = \frac{n}{2} (2a + (n - 1)d) \\ = \frac{100}{2} (2(1) + (100 - 1)(1) \\ = 50(2 + 99) \\ = 50 \times 101 \\ = 5050$

Sum of all natural numbers from 1 to 100 = 5050

Hope you get your answer

Answer 2

Answer:

5050

Step-by-step explanation:

n(n+1)/2

=100(100+1)/2

=100(101)/2

=10100/2

=5050