THE SUM OF ALL NATURAL NUMBERS FROM 1 TO100IS
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Answered by
2
the natural no.s from 1 to 100
1,2,3,4,5,6.................100
a = 1
d = 1
n = 100
Sn = n/2(2a+(n-1)d)
= 100/2 (2+99)
= 50 (101)
= 5050
1,2,3,4,5,6.................100
a = 1
d = 1
n = 100
Sn = n/2(2a+(n-1)d)
= 100/2 (2+99)
= 50 (101)
= 5050
Answered by
0
answer is 5050.
first natural number is 1 ,last natural number is 100 from given data .then total natural numbers between 1to 100 are 100.
so by calculating as follows we get,
(1+100)/2×100=5050
first natural number is 1 ,last natural number is 100 from given data .then total natural numbers between 1to 100 are 100.
so by calculating as follows we get,
(1+100)/2×100=5050
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