The sum of all numbers between
I and looo
which aredivisible by 3
Answers
Answered by
1
Answer:
How many numbers from 1 to 1000 is divisible by 3?
Let’s break the range into one, two and three digit numbers respectively.
1 - 9 -> 3 , 6 , 9 => Three nos in this range = 3
10 - 99 -> 12, 15, 18 …..,99 => Thirty nos in this range { we can get the value of n by using the nth term formula i.e [a + (n-1) * d] } = 30
100–999 -> 102,105,…..,999 => Three hundred nos in this range = 300
We are left out with 1000 and we can make out that it is not divisible by 3.
Hence, total numbers between 1 and 1000 divisible by 3 = 3 + 30 + 300 = 333.
333 is your answer.
Step-by-step explanation:
Answered by
1
It’s AP
Where
a = 3
d = 3
Last term L= 999
999 = 3 + ( n-1 ) 3
999 = 3 n
n = 333
Sum AP = n/2 ( a + L)= 333/2 ( 3 + 999)
= 333 + 501
= 834
Where
a = 3
d = 3
Last term L= 999
999 = 3 + ( n-1 ) 3
999 = 3 n
n = 333
Sum AP = n/2 ( a + L)= 333/2 ( 3 + 999)
= 333 + 501
= 834
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