Question

the sum of all odd integers between 2 and 100 divisible by 3 is

Answer 1

Answer:

hey mate

Step-by-step explanation:

The odd integers between 2 and 100 which are divisible by 3 are 3, 9, 15, 21, ..., 99.

Here, a=3 and d=6.

an=99

⇒a+(n−1)d=99

⇒3+(n−1)×6=99

⇒6(n−1)=96

⇒n−1=16

⇒n=17

Therefore,

Required sum = n/2 (a+l) = 17/3(3+99) = 867

hope it helpful

Answer 2

Plz mark it as brainliest