Math, asked by devia6248, 5 months ago

The sum of all odd integers between 2and 300 is divisible by 3 is​

Answers

Answered by Anonymous
2

Answer:

The odd integers between 2 and 100 which are divisible by 3 are 3, 9, 15, 21, ..., 99.

Here, a=3 and d=6.

a

n

=99

⇒a+(n−1)d=99

⇒3+(n−1)×6=99

⇒6(n−1)=96

⇒n−1=16

⇒n=17

Therefore,

Required sum = n/2 (a+1)= 17/2 (3+99)=867

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