Question

the sum of all odd integers between.2and100 divisible by 3 is​

Answer 1

Answer:

869

Step-by-step explanation:

The odd integers between 2 and 100 which are divisible by 3 are 3, 9, 15, 21, ..., 99

Here, a=3 and d=6.

an=99

⇒a+(n−1)d=99

⇒3+(n−1)×6=99

⇒6(n−1)=96

⇒n−1=16

⇒n=17

Therefore,

Required sum =n/2(a+l)=17/2(3+99)=867

Hope it is helpful..!!

Answer 2

$\huge\bold\red{ANSWER....}$

The odd integers between 2 and 100 which are divisible by 3 are 3, 9, 15, 21, ..., 99.

Here,

a = 3

d = 8

$n_{a}$

a + (n-1) = 99

3 + (n-1) × 6 = 99

(n-1) ×6 = 99 - 3

(n-1) = 96/6

n - 1 = 16

n = 16 +1

n = 17

Therefore,

Sun of odd numbers = $\sf\frac{n}{2}\:(a\:+\:t)$

$\longrightarrow\sf\frac{17}{2}\:(3\:+\:99)$

$\longrightarrow\huge\bold{867}$