Question

The sum of all possible values of n, where n is a non-zero integer when n ^ 2 + 8n + 6 is divided by n gives an integer, is​

Answer 1

Explanation:

hope its helpful

N is least positive integer and when a digit c is written after last digit of N, the resulting number is divisible by c.

⇒ So,

c

(N)c

Least positive integer (N) which is divisible by digit c i.e. (1−9)

So possible number is

⇒

c

(9×8×7×5)c

Number, 9×8×7×5 is divisible by all the digits from 1 to 9

⇒ So, Number is 72×35=2520=N

⇒ Sum of the digits of number N=2+5+2+0=9