The sum of all solutions of the equation
tan 2θ = tan 2
i
in the interval [0, 2π] is
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Step-by-step explanation:
tan2θ+23tanθ=1
tan2θ+23tanθ−1=0
Add +4 on both sides
tan2θ+23tanθ+3=4
(tanθ+3)2=4
tanθ+3=±2
tanθ=2−3, tanθ=−(2+3)
tan(12π) tan(2−π)
x=nπ±12π for n=0,1,2…..
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