Question

The sum of all the multiples of 3 from 100 to 200 is

Answer 1

Answer:

6633

Step-by-step explanation:

Last Term) = a+(n-1)d

a - First term

d - Common Difference

n - Number of terms

The multiples of 3 from 1 to 200 are 3,6,9,12,....,198

a = 3

d = 3

TnTn = 198

Now, Using the formula

198 = 3+(n-1)3

Solving Gives,

n = 66

Now, Sum of all the terms in AP is given by

SnSn = n2n2[2a+(n-1)d]

S66S66 = 662662[2*3+(66-1)3]

S66S66 = 33[6+195]

S66S66 = 6633

Answer 2

Answer:

this is the right answer