The sum of all the natural numbers between 1 and 101 which are divisible by 5
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1
Answer:
680
Explanation:
an: a+(n-1)d
100: 5+(n-1)5
n: 16
Sn: n/2(2a+(n-1 )d)
Sn: 16/2 (10+75)
Sn: 8x85
Sn:680
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