Question

the sum of all the numbers between 1 and 200 which are multiple of 4 is​

Answer 1

$<font color= "red">$Answer:

$<font color= "Black">$A=4

d=4

tn= a+(n- 1)d

196=4+(n- 1)4

n- 1=192/4

n -1=48

n=49

Sn=n/2(a+t n)

=49/2(4+196)

=49/2(200)49 ,

200/2= 10049(100 )

= 49 multiply 100 = 4900

$<marquee><font color= "red">$I hope it will helps you to guide and mark me brainliest ♥