Question

the sum of all the numbers from 1 to 100 which are multiples of 4 or 5 is​

Answer 1

Multiples of :

4 => 4, 8, 12 ,16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100

5=> 5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95,100

total numbers => 44

sum of all the numbers => 2350

hope it helps !!

Answer 2

Step-by-step explanation:

the sum of all the nos. from 1 to 100 which are multiples of 4:-

4+8+12+..........+a^n

a^n= a1 + (n-1) (4)

= 4+99(4)

400=4+396

s^n= n/2(a1+an)

=100/2 (4+400)

50(404)=20200

the sum of all the nos. from 1 to 100 which are multiples of 5:-

first of all,how many multiples of 5 are there from 1 to 100?assuming we're including 100, there are 20.this is trivial to demonstrate:count up by 5s and you'll reach 100 on your 20th count.

5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95,100

now let's think about pairing nos. if we pair 5 and 100, we get 105.

5+100= 105

and if we pair 10 and 95 we also get 105

10+ 95= 105

in fact we can make ten pairs of nos. that add up to 105.

15+90=105

20+ 85=105

and so on....

10×105=1050

HOPE ITS HELPS....

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