Question

the sum of all the three digit number​

Answer 1

hey mate ,

The sequence so formed = 100,101......999

A = 100

D = 1

An = 999

An = A +(n-1)D

999=100+(n-1)1

899= n-1

n = 900

Sn = n/2 ( A+An)

= 900/2 (1+999)

= 450 × 1000

= 450000

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